alrighty
add 6 to both sides and minus x² from both sides
√(3x)=6-x²
square both sides
3x=x⁴-12x²+36
minus 2x both sides
0=x⁴-12x²+3x+36
group and factor
how you do that
magic (I used my calculator)
we get
0=(x-3)(x-1.90057)(x²+4.90057x+6.13189)
set equal to 0
0=x-3
3=x
0=x-1.90057
1.90057=x
and the other one doesn't intersect have a 0
so the solutions are x=3 and x=1.90057
hold a second
if we test x=1.90057, we get a true statemtnt
but if we test x=3, we get 12=0 which is false
the only solution is x=1.90057
