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At 25.0∘C, the molar solubility of barium chromate in water is 1.10×10−5 M . Calculate the solubility in grams per liter.

Answer :

Willchemistry
Hey there!

Molar mass :

 ‎BaCrO4 =  ‎253.319 g/mol

(g/L) = molar solubility * molar mass

(g/L) =  ( 1.10 x 10⁻⁵ ) * 253.319

=> 2.79x10⁻³ g/L

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