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A ball rolls along a smooth horizontal floor at 10 m/s, then starts up a 20 degree ramp. How high does it go before rolling back?

Answer :

If we neglect friction then only mgsin20 lower the speed of the ball
ma=mgsin20
a=gsin20=3.4 m/s^2
of course we insert it next formula with a negative because the speed decreases
v^2-v0^2=2ah
100-0=6.8h
h=100/6.8=14.7 m

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