At what points do these graph intersects?
y= x^2 + 3x - 6
y= x + 2
Seth's Solution
y = x^2 + 3x - 6
y= x + 2
x^2 + 3x - 6= x + 2
x^2 + 2x - 8 = 0
(x + 4 ) ( x- 2 ) = 0
x = -4 and x = 2
The graph intersects at (-4, 0 ) and (2,0)
Is Seth's Solution correct? Explain​