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Suppose you were calibrating a 50.0 ml volumetric flask using distilled water. the flask temperature was at 20°c, and you assumed that the distilled water was as well. however, you later discover that the actual water temperature was 14°c instead. how is the mass of the 50.0 ml of distilled water you measured at 14°c different from the mass of 50.0 ml of distilled water at 20°c?

Answer :

meerkat18
Density is sensitive to temperature for gases and liquids, although not much for liquids. We use the data in the picture. Using linear interpolation, we determine the densities at 14°C and 20°C.

@20°C: Density = 0.99823 g/cm³ or g/mL
@14°C:
(10 - 14)/(10 - 20) = (0.99973 - Density)/(0.99973 - 0.99823)
Solving for density:
Density = 0.99913 g/cm³ or g/mL

Mass @ 20°C = 50 mL *  0.99823 g/mL = 49.9115 g
Mass @ 14°C = 50 mL *  0.99913 g/mL = 49.9565 g
Difference of Masses = |49.9115 g - 49.9565 g| = 0.045 g
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