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Silver chloride, often used in silver plating, contains 75.27% ag. part a calculate the mass of silver chloride required to plate 135 mg of pure silver.

Answer :

Kalahira Kalahira

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179.35 mg of silver chloride is required to plate 135 mg of silver. Create an expression showing what you know. Namely that 75.27% of X is equal to 135. So we get 75.27% X = 135 0.7527 X = 135 Now divide both sides by 0.7527 X = 135 mg / 0.7527 = 179.3543 mg So it will take 179.35 mg of silver chloride to plate out 135 mg of pure silver.

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