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The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the first number. Find the integers. I hate math.

Answer :

rabinshrestha41
Given,
The sum of three integers is 92

So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"

Now,
According to the question,
y = 3x          ..............equation (1)
z = 2x - 10    .............. equation (2)
x + y + z = 92 ..............equation (3)

Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,

x + (3x) + (2x - 10) = 92
    x + 3x + 2x - 10 = 92
                  6x - 10 = 92
                         6x = 92 + 10
                           x = 102 / 6
                           x = 17

Now,
substituting the value of "x" in equation (1)
 y = 3 (17)
y = 51

Now,
Substituting the value of "x" in equation (2),

z = 2 (17 ) - 10
z = 34 - 10
z = 24


So, the numbers are 17, 51 and 24


NEVER HATE MATH!!!

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