Answer :

Iron (III) Chloride: [tex]FeCl_3[/tex]
Silver Sulfite [tex]Ag_2SO_3[/tex]

[tex]FeCl_3 + Ag_2SO_3 --\ \textgreater \ Fe_2(SO_3)_3 + AgCl [/tex]

Balanced equation:
[tex]2FeCl_3 + 3 Ag_2SO_3 = Fe_2(SO_3)_3 + 6AgCl[/tex]

Hope this Helps :)

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