Answer :
Iron (III) Chloride: [tex]FeCl_3[/tex]
Silver Sulfite [tex]Ag_2SO_3[/tex]
[tex]FeCl_3 + Ag_2SO_3 --\ \textgreater \ Fe_2(SO_3)_3 + AgCl [/tex]
Balanced equation:
[tex]2FeCl_3 + 3 Ag_2SO_3 = Fe_2(SO_3)_3 + 6AgCl[/tex]
Hope this Helps :)
Silver Sulfite [tex]Ag_2SO_3[/tex]
[tex]FeCl_3 + Ag_2SO_3 --\ \textgreater \ Fe_2(SO_3)_3 + AgCl [/tex]
Balanced equation:
[tex]2FeCl_3 + 3 Ag_2SO_3 = Fe_2(SO_3)_3 + 6AgCl[/tex]
Hope this Helps :)