Answered

Nitrogen reacts with hydrogen to produce ammonia gas as follows.

mc023-1.jpg

How many moles of nitrogen would react with excess hydrogen to produce 520 mL of ammonia?
0.0116 mol
0.012 mol
0.0232 mol
0.024 mol

Answer :

kenmyna

The  moles of nitrogen   that would react with excess hydrogen  to produce 520 ml of ammonia is   0.011  moles


calculation

step 1: write the balanced equation  for reaction

=  N2  + 3 H2 → 2NH3


step 2: find the moles of NH3 produced

  • convert 520 Ml into liters =  520/1000= 0.52 L
  • At STP  1 moles of gas = 24 L

                                           ?    =  0.52 L

  • by  cross multiplication

(0.52 L x 1  mole) / 24 L  =0.02167  moles of NH3


step 3:  use  mole ratio to determine the moles of  Nitrogen


the mole ratio of N2:NH3 =  1:2

therefore the moles of N2= 0.02167  x1/2=0.011 moles    of N2

jjjcmsjenn

Answer:

A: 0.0116 mol

Explanation:

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