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The length of each side of a square increases by 2.5 inches to form a new square with a perimeter of 70 inches. The length of each side of the original square was inches. NextReset

Answer :

kritter1
Let x be the original side length of the square

P=2(l+w) 
70=2((2.5+x)+(2.5+x))
70=2(5+2x) 
70/2 = 5+2x 
35-5=2x
30=2x
15=x 

Therefore, the original length of the square was 15" 

Hope I helped :) 
calculista

Answer:

The length of each side of the original square was [tex]15[/tex] inches

Step-by-step explanation:

Let

x------> the length side of the original square

we know that

The perimeter of a square is equal to

[tex]P=4b[/tex]

where

b is the length side of the square

In this problem

[tex]b=(x+2.5)\ in[/tex]

[tex]P=70\ in[/tex]

substitute

[tex]70=4(x+2.5)[/tex]

solve for x

[tex]70=4x+10[/tex]

[tex]4x=70-10[/tex]

[tex]x=60/4=15\ in[/tex]

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