Answered

If a photon has a frequency of 5.20 x 10^14 hertz, what is the energy of the photon ?
Given : Planck's constant is 6.63 x 10^-34 joule-seconds.

Answer :

TheProfessor4zzzFM
For this you would use planck's equation.

E = hv, where v = the frequency and h = planck's constant.

So E = 5.20 x10^14  x  6.63 x 10^-34
= 3.45 x 10^-19 Joules

Other Questions