Answer :
number of moles of KOH = mass/molar mass
number of moles of KOH = 0.477/204.22 = 2.3357x10^-3 moles
Now, number of moles of NaOH is equal to the number of moles of KOH, this means that:
number of moles of NaOH = 2.3357x10^-3 moles
molarity can be calculated using the following rule:
molarity = number of moles of solute/liters of solution
molarity of NaOH = (2.3357x10^-3) / ( 0.03678) = 0.0635 molar
Based on this, stock of NaOH = 0.0635 molar
number of moles of KOH = 0.477/204.22 = 2.3357x10^-3 moles
Now, number of moles of NaOH is equal to the number of moles of KOH, this means that:
number of moles of NaOH = 2.3357x10^-3 moles
molarity can be calculated using the following rule:
molarity = number of moles of solute/liters of solution
molarity of NaOH = (2.3357x10^-3) / ( 0.03678) = 0.0635 molar
Based on this, stock of NaOH = 0.0635 molar
The molarity of NaOH solution is [tex]\boxed{{\text{0}}{\text{.0635 M}}}[/tex]
Further Explanation:
The concentration is the proportion of substance in the mixture. The most commonly used concentration terms are as follows:
1. Molarity (M)
2. Molality (m)
3. Mole fraction (X)
4. Parts per million (ppm)
5. Mass percent ((w/w) %)
6. Volume percent ((v/v) %)
Molarity is a concentration term that is defined as the number of moles of solute dissolved in one litre of the solution. It is denoted by M, and its unit is mol/L.
The formula to calculate the molarity of NaOH solution is as follows:
[tex]{\text{Molarity of NaOH solution}}=\frac{{{\text{amount}}\;\left({{\text{mol}}} \right)\;{\text{of}}\;{\text{NaOH}}}}{{\;{\text{volume }}\left({\text{L}}\right)\;{\text{of}}\;{\text{NaOH solution}}}}[/tex] ...... (1)
Firstly the volume is to be converted into L. The conversion factor for this is,
[tex]{\text{1 mL} ={\text{1}}{{\text{0}}^{{\text{-3}}}}{\text{ L}}[/tex]
So the volume of NaOH solution can be calculated as follows:
[tex]\begin{aligned}{\text{Volume of NaOH solution}}&=\left({{\text{36}}{\text{.78 mL}}}\right)\left({\frac{{{\text{1}}{{\text{0}}^{-3}}{\text{ L}}}}{{{\text{1 mL}}}}}\right)\\&=0.03678\;{\text{L}}\\\end{aligned}[/tex]
The number of moles of KHP can be calculated as follows:
[tex]{\text{Moles of KHP}} = \frac{{{\text{Given mass of KHP}}}}{{{\text{Molar mass of KHP}}}}[/tex] …… (2)
The given mass of KHP is 0.477 g.
The molar mass of KHP is 204.22 g/mol.
Substitute these values in equation (2).
[tex]\begin{aligned}{\text{Moles of KHP}}&=\left({{\text{0}}{\text{.477 g}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{204}}{\text{.22 g}}}}}\right)\\&={\text{0}}{\text{.0023357 mol}}\\\end{aligned}[/tex]
Since KHP is a monoprotic acid and NaOH is also monobasic. Therefore equal moles of KHP and that of NaOH will react and thus become equal. The moles of NaOH is 0.0023357 mol.
The moles of NaOH are 0.0023357 mol.
The volume of NaOH solution is 0.03678 L.
Substitute these values in equation (1).
[tex]\begin{aligned}{\text{Molarity of NaOH solution}}&=\frac{{{\text{0}}{\text{.0023357 mol}}}}{{{\text{0}}{\text{.03678 L}}}}\\&={\text{0}}{\text{.063504 M}}\\&\approx {\text{0}}{\text{.0635 M}}\\\end{aligned}[/tex]
So the molarity of NaOH solution is 0.0635 M.
Learn more:
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Concentration terms
Keywords: molarity, NaOH, KHP, monoprotic, amount of NaOH, molarity of NaOH solution, 0.003678 L, 36.78 mL, 0.0635 M, molarity of NaOH solution, 0.477 g and 204.22 g/mol.