Answer :
in an arithmetic sequence, the nth term is the first term + (n-1)* difference
the fifth term=the second term +(5-2)*difference
22=10+3d
d=4
the first term=the second term-the difference=10-4=6
the nth term =6+4(n-1) or or 10+4(n-2),
the fifth term=the second term +(5-2)*difference
22=10+3d
d=4
the first term=the second term-the difference=10-4=6
the nth term =6+4(n-1) or or 10+4(n-2),