Answer :
The representation of this problem is shown in the figure below. As you can see there are 5 rectangles.
In the plane, there are 5 horizontal sides. The horizontal side of each rectangle is as follows:
[tex]2x+7[/tex]
Therefore, the horizontal fencing is given by:
[tex]H=5(2x+7)=10x+35[/tex]
On the other hand, there are 6 vertical sides. The vertical side of each rectangle is given by:
[tex]x[/tex]
Therefore, it is true that the vertical fencing is:
[tex]V=6x[/tex]
Accordingly, the total fencing is:
[tex]H+V=(10x+35)+(6x)=16x+35[/tex]
In the plane, there are 5 horizontal sides. The horizontal side of each rectangle is as follows:
[tex]2x+7[/tex]
Therefore, the horizontal fencing is given by:
[tex]H=5(2x+7)=10x+35[/tex]
On the other hand, there are 6 vertical sides. The vertical side of each rectangle is given by:
[tex]x[/tex]
Therefore, it is true that the vertical fencing is:
[tex]V=6x[/tex]
Accordingly, the total fencing is:
[tex]H+V=(10x+35)+(6x)=16x+35[/tex]
Answer:
[tex]16x+35[/tex]
Step-by-step explanation:
Given that a piece of land is to be fenced and subdivided as shown so that each rectangle has the same dimensions. Express the total amount of fencing needed as an algebraic expression in
there are 5 sides and one of them is just x and the other is 2x+7
Since there are 5 sides with one of them is just x, we have to fence all the 6 partitions so we require 6x wires for fencing.
FOr length, we find that one side is not to be fenced other side has 5 times 2x+7 length = 10x+35
So total fence required [tex]= 10x+35+6x\\=16x+35[/tex]