Answer :
40.0 gC x 1 mol C/12.0 gC=3.33 moles of C ----- divide by smallest
6.67 gH x 1 mol H/ 1.0 gH= 6.7 moles of H ------ CH2O= (12 + 2 + 16)= 30g
53.3 gO x 1mol O/ 15.0 gO=3.33 moles of O ----- 150g/30g= 5x
=C5H10O5
6.67 gH x 1 mol H/ 1.0 gH= 6.7 moles of H ------ CH2O= (12 + 2 + 16)= 30g
53.3 gO x 1mol O/ 15.0 gO=3.33 moles of O ----- 150g/30g= 5x
=C5H10O5