Answer :

(2x+10)/10 = (x+3)/4
10(x+3) = 4(2x+10)
10x + 30 = 8x + 40
2x = 10
x = 5

so
AE = 2(5) +10
AE = 10 + 10
AE = 20
calculista

Answer:

[tex]AE=20\ units[/tex]

Step-by-step explanation:

we know that

If AB is parallel to CD

then

triangles ABE and EDC are similar

Remember that

If two triangles are similar

then

the ratio of their corresponding sides is equal and their corresponding angles are equal too

In this problem

[tex]\frac{AE}{ED}=\frac{AB}{CD}[/tex]

substitute the values and solve for x

[tex]\frac{2x+10}{x+3}=\frac{10}{4}[/tex]

[tex]4(2x+10)=10(x+3)\\8x+40=10x+30\\10x-8x=40-30\\2x=10\\x=5\ units[/tex]

Find the length of AE

[tex]AE=2x+10[/tex] -----> substitute the value of x

[tex]AE=2(5)+10=20\ units[/tex]

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