Answer :
Let AB extended intersect DC extended at point E
We now have right triangle BEC with E = 90 degrees
For triangle BEC:
Exterior angle at E = 90
Exterior angle at C = 148 (given)
Exterior angle of all polygons add up to 360 degrees
Exterior angle at B = 360−148−90 = 122
So in quadrilateral ABCD
B = 122
D = 360−44−148−122 = 46
We now have right triangle BEC with E = 90 degrees
For triangle BEC:
Exterior angle at E = 90
Exterior angle at C = 148 (given)
Exterior angle of all polygons add up to 360 degrees
Exterior angle at B = 360−148−90 = 122
So in quadrilateral ABCD
B = 122
D = 360−44−148−122 = 46