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Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5).

Write the equation of this cubic polynomial function.

Recall that the zeroes are (2, 0), (3, 0), and (5, 0). What is the y-intercept of this graph?
-5

The linear factors of the cubic are

Answer :

Catya
Zeros are the x values which make the function equal to zero. Set it up as you would for a binomial with a constant multiplier "k" to account for the y-intercept (0, -5) given.

f(x) = k(x-2)(x-3)(x-5)

Use the y-intercept (0,-5) to solve for k.

-5 = k(0-2)(0-3)(0-5)
-5 = -30k
-5/-30 = k
1/6 = k


The cubic polynomial function is then ..

f(x) = (1/6)(x-2)(x-3)(x-5)
 

Linear factors are the linear (line) expressions you can factor out of the polynomial. They are (x-2), (x-3) and (x-5).


The cubic polynomial equation which passes through the coordinate (0,-5) and whose zeroes are (2 , 0), (3 , 0), and (5 , 0) is: [tex]y = \dfrac{1}{6}(x-2)(x-3)(x-5)[/tex] and it can be determine by arithmetic operations.

Given :

  • A cubic polynomial whose zeroes are (2 , 0), (3 , 0), and (5 , 0).
  • Cubic polynomial equation passes through (0 , -5).

Arithmetic operations can be used to determine the cubic polynomial equation. The generalised cubic polynomial equation is given by:

[tex]y = K(x-a)(x-b)(x-c)[/tex]

Where, K is constant and a, b, and c are the zeroes of the cubic polynomial equation. Therefore, the value of a, b, and c are 2, 3, and 5 respectively.

[tex]y = K(x-2)(x-3)(x-5)[/tex]   ----- (1)

It is given that cubic polynomial equation passes through (0 , -5). So, put x = 0 and y = -5 in equation (1) to evaluate the value of K.

[tex]-5=K(0-2)(0-3)(0-5)[/tex]

[tex]5=30K[/tex]

[tex]K = \dfrac{1}{6}[/tex]

Therefore the cubic polynomial equation is given by:

[tex]y = \dfrac{1}{6}(x-2)(x-3)(x-5)[/tex]

For more information, refer the link given below:

https://brainly.com/question/12254880

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