Answer :

Willchemistry
hey there!:

Temperature in kelvin :

20.0ºC + 273 => 293 K

R = 0.082

Volume =7.00 L

Pressure = 5.45 atm

Number of moles = ??

Therefe:

P * V = n * R * T

5.45 * 7.00 = n * 0.082 * 293

38.15 = n * 24,026

n = 38.15 / 24.026

n = 1.587 moles of propane ( C3H8 )

hope this helps!


nuhulawal20

the amount of propane in the tank at the given temperature and pressure is 1.59moles.

Given the data in the question;

  • Volume of tank; [tex]V = 7.00L[/tex]
  • Temperature; [tex]T = 20.0^oC = 293.15K[/tex]
  • Pressure; [tex]P = 5.45atm[/tex]
  • Amount of propane; [tex]n = \ ?[/tex]

Ideal Gas Law

The Ideal gas law states "that pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature. It is expressed;

[tex]PV = nRT[/tex]

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( [tex]R = 0.08206Latm/molK[/tex] ).

The determine the amount of propane in the tank, we substitute our given values into the equation above.

[tex]PV = nRT\\\\5.45atm * 7.00L = n * 0.08206Latm/molK * 293.15K\\\\38.15Latm = n * 24.055889Latm/mol\\\\n = \frac{38.15Latm}{24.055889Latm/mol}\\ \\n = 1.59moles[/tex]

Therefore, the amount of propane in the tank at the given temperature and pressure is 1.59moles.

Learn more about the Ideal gas law here: https://brainly.com/question/4147359

Other Questions