Answer :
Let
x-------> one number
y--------> another number
we know that
x=6y--------> equation 1
(1/x)+(1/y)=14/3-----> (x+y)/xy=14/3-----> 3*(x+y)=14xy-----> equation 2
I substitute 1 in 2
3*(6y+y)=14(6y)y------> 21y=84y²-----> y=0.25
x=6y-----> x=6*0.25-----> x=1.5
the answer is
the numbers are 1.5 and 0.25
x-------> one number
y--------> another number
we know that
x=6y--------> equation 1
(1/x)+(1/y)=14/3-----> (x+y)/xy=14/3-----> 3*(x+y)=14xy-----> equation 2
I substitute 1 in 2
3*(6y+y)=14(6y)y------> 21y=84y²-----> y=0.25
x=6y-----> x=6*0.25-----> x=1.5
the answer is
the numbers are 1.5 and 0.25