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A point charge of 6.0 C is placed 5.0 mm from a rod that has an electric field of 2.4 x 10 N/C The electric potential energy of the point charge (rounded to two significant figures) is J.

Answer :

mexican18
The formula in solving the Electric potential nergy energy of a point is:V = (k*Q) / r
We have the given values in the number:r= 5mm * (1m/1000mm) = 0.005 mQ = 6 CK = 2.4 N/C
Solving for the Electric Potential energy is shown:V= (2.4*6)/0.005V = 2880 Joules

Answer is 72 joules.

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