Answer :
Answer: 24
Explanation
1) The given function is understood to be f(x) = logaritm base 5 of (x + 1)
That is:
[tex]f(x)=log_5(x+1)[/tex]
2) You want f−1(2), which is the inverse function at x = 2
And the options are:
f−1(2) = 3
f−1(2) = 11
f−1(2) = 18
f−1(2) = 24
The answser is the fourth option 24.
This is how you find it.
1) The inverse fucntion of
[tex]f(x) = y = log_5(x+1)[/tex]
is
[tex]5^y=x+1[/tex]
Swap x and y:
5ˣ = y + 1
From which, it follows:
y = 5ˣ - 1
Now just replace x = 2
=> y = 5² - 1 = 25 - 1 = 24
Which is the answer (the fourth option).
Explanation
1) The given function is understood to be f(x) = logaritm base 5 of (x + 1)
That is:
[tex]f(x)=log_5(x+1)[/tex]
2) You want f−1(2), which is the inverse function at x = 2
And the options are:
f−1(2) = 3
f−1(2) = 11
f−1(2) = 18
f−1(2) = 24
The answser is the fourth option 24.
This is how you find it.
1) The inverse fucntion of
[tex]f(x) = y = log_5(x+1)[/tex]
is
[tex]5^y=x+1[/tex]
Swap x and y:
5ˣ = y + 1
From which, it follows:
y = 5ˣ - 1
Now just replace x = 2
=> y = 5² - 1 = 25 - 1 = 24
Which is the answer (the fourth option).