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An astronaut drops a rock into a crater on the moon the distance d(t), in meters, the rock travels after T seconds can be modeled by the function d(t)= .8t^2.what is the average speed in meters per second of the rock between five and 10 seconds after it was dropped

Answer :

sqdancefan
  speed = distance/time
The average speed will be the change in distance divided by the change in time.
  (d(10) -d(5))/(10 -5) = (80 -20)/5 = 12 . . . . meters per second
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