Answer :
Compare this function to y=ax^2 + bx + c. You can readily see that a=2, b=0 and c=6.
The x-coord. of the vertex is at x = -b / (2a). Subbing the given values for a and b, we get
x = -(0) / (2(2) = 0. At x = 0, y = 6, so the vertex of this parabola is (0,6). It opens upward.
The x-coord. of the vertex is at x = -b / (2a). Subbing the given values for a and b, we get
x = -(0) / (2(2) = 0. At x = 0, y = 6, so the vertex of this parabola is (0,6). It opens upward.