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A golf ball is selected at random from a golf bag. if the golf bag contains 9 type a​ balls, 8 type b​ balls, and 3 type c​ balls, find the probability that the golf ball is not a type a ball.

Answer :

Total number of balls = 9 + 8 + 3 = 20

P(not type a ball) = 11/20

Answer: 11/20
penfila11Pen
Hey there :)

Lets translate the sentences into mathematics:
Contains type a ball = 9
Contains type b ball = 8
Contains type c ball = 3
Total = 9 + 8 + 3 = 20

Type a fraction = [tex] \frac{9}{20} [/tex] 

If ball chosen at random is not a type a golf ball
[tex] \frac{type(B)+type(C)}{20} = \frac{8+3}{20} = \frac{11}{20} [/tex]

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