we know that A right isosceles triangle has two equal sides and two equal angles so has two angles equals to 45°
methodology 1 to solve the problem Let x--------> length of the leg of triangle sin 45°=opposite side/hypotenuse sin 45°=√2/2 opposite side=hypotenuse*sin 45°------> 31*√2/2---> 21.92 units
methodology 2 to solve the problem c²=a²+b² c=hypotenuse------> 31 units a=leg 1 b=leg 2 a=b so c²=2a²------> a²=c²/2------> a²=(31)²/2 a=√[(31)²/2]------> a=31/√2-----> 31√2/2------> 21.92 units
