Answer :
To solve this problem you must apply the proccedure shown below:
1. You have the the line y=2x-4 is dilated by a scale factor of 3/2 and centered at the origin.
2. The form of the a line is y=mx+b, where m is the slope and b is the y-intercept. As dilation conserves the parallelism, the dilated linw will have the same slolpe: 2
m=2
3. By using the y-intercept, you have:
(0,-4)
0x3/2=0
-4(3/2)=-6
(0,-6)
4. Therefore, the equation that represent that image of the line after dilation is:
m=2
b=-6
y=2x-6
1. You have the the line y=2x-4 is dilated by a scale factor of 3/2 and centered at the origin.
2. The form of the a line is y=mx+b, where m is the slope and b is the y-intercept. As dilation conserves the parallelism, the dilated linw will have the same slolpe: 2
m=2
3. By using the y-intercept, you have:
(0,-4)
0x3/2=0
-4(3/2)=-6
(0,-6)
4. Therefore, the equation that represent that image of the line after dilation is:
m=2
b=-6
y=2x-6
The equation that represent that image of the line after dilation is
[tex]y = 2x-6[/tex]
Given :
The line [tex]y=2x-4[/tex] is dilated by a scale factor of [tex]3\div2[/tex] and centered at the origin.
Solution :
The given line has slope 2 and y intercept -4.
As dilation conserves the parallelism, the dilated line will have the same slope = 2 and the y intercept of the dilated line is
[tex]= -4\times \dfrac{3}{2}=-6[/tex]
Therefore the equation that represent that image of the line after dilation is
[tex]y = 2x-6[/tex]
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