Answer :
f(n) = -6.5n + 14.5
f(n) = 8, f(n+1) = f(n) -6.5
The first is the explicit definition, the other one is the corresponding recursive definition. In this sequence we can note that the first term f(1) is 8, the f(0) term is 14.5, and the difference d= -6.5.
f(n) = 8, f(n+1) = f(n) -6.5
The first is the explicit definition, the other one is the corresponding recursive definition. In this sequence we can note that the first term f(1) is 8, the f(0) term is 14.5, and the difference d= -6.5.
Answer:
f(n) = –6.5n + 14.5
f(1) = 8, f(n + 1) = f(n) – 6.5
Step-by-step explanation:
The nth term of an arithmetic sequence is given as
Tn = a + (n-1)d
where a is the first term and d is the common difference between two consecutive terms
From the given sequence,
a = 8, d = 1.5 - 8
d = -6.5
As such, Tn = f(n) = 8 + (n-1)-6.5
= 8 - 6.5n + 6.5
= 14.5 - 6.5n
f(1) = 8
f(n + 1) - f(n) = – 6.5
f(n + 1) = f(n) – 6.5