Answer :
[tex]2(3y-1)+3(y-4)=13\\\\2\cdot3y+2\cdot(-1)+3\cdot y+3\cdot(-4)=13\\\\6y-2+3y-12=13\\\\\underbrace{6y+3y}_{9y}\underbrace{-2-12}_{-14}=13\\\\9y-14=13\ \ \ |\text{add 14 to the both sides}\\\\9y=27\ \ \ |\text{divide both sides by 9}\\\\\boxed{y=3} [/tex]