Answer :
From the expression 8(x +4) (y +4) (z 2 + 4z + 7),
the factors are 8, (x+4), (y+4), (z^2 + 4z + 7) since each of these factors, when you divide that to the whole expression won't give a remainder.
the factors are 8, (x+4), (y+4), (z^2 + 4z + 7) since each of these factors, when you divide that to the whole expression won't give a remainder.
Answer:
Only 2 factors have exactly two terms i.e, (x+4)(y+4)
Step-by-step explanation:
Given : Expression [tex]8(x+4)(y+4)(z^2+4z+7)[/tex]
To find : How many factors in the expression have exactly two terms?
Solution :
Expression [tex]8(x+4)(y+4)(z^2+4z+7)[/tex] cannot be further factorized.
Now, We count the terms in each factor.
1) Factor- 8
Only 1 term i.e, 8 itself.
2) Factor- x+4
Two terms .i.e., x and 4
3) Factor- y+4
Two terms .i.e., y and 4
4) Factor- [tex]z^2+4z+7[/tex]
Three terms .i.e., [tex]z^2[/tex], 4z and 7.
Therefore, Only 2 factors have exactly two terms i.e, (x+4)(y+4).
