Answer:
14.35 ft.
Step-by-step explanation:
We have 2 right-angled triangles so we can apply the Pythagoras theorem to each one:
14^2 = 12^2 + BC^2
BC^2 = 14^2 - 12^2 = 52
BC = √52 = 7.21.
10^2 = 7^2 + CD^2
CD^2 = 100 - 49 = 51
CD = √51 = 7.14.
So the distance between the 2 poles = BC + CD
= 14.35 ft.
The distance between B and D is 14.35 ft if two poles, AB and ED, are fixed to the ground with the help of ropes AC and EC option (C) is correct.
It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.
From the right angle triangle ABC:
14² = 12² + BC²
BC = √52 = 7.21 feet
In right angle triangle DCE
10² = 7² + CD²
CD = √51 = 7.14 feet
BD = BC + CD = 7.21 + 7.14
BD = 14.35 ft
Thus, the distance between B and D is 14.35 ft if two poles, AB and ED, are fixed to the ground with the help of ropes AC and EC option (C) is correct.
Learn more about the right angle triangle here:
brainly.com/question/3770177
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