Answer :
Answer:
0.0014 weber
Explanation:
We have given side of the square loop = 5 cm =0.05 meter
Area of the square loop A = 0.05×0.05=0.0025 [tex]m^2[/tex]
It is given that magnetic field vector is perpendicular to the the face of the loop so the area vector and the magnetic field vector will be parallel to each other so angle between magnetic field and area will be zero
According to Lenz law magnetic flux [tex]\Phi =B.A=BAcos\Theta[/tex] here [tex]\Theta[/tex] is the angle between the magnetic field vector and the area vector
We have also given B = 0.56 T
So [tex]\Phi =0.56\times 0.0025\times cos0=0.0014\ weber[/tex]