Answer :

Answer:

a) 3AC => 001110101100

b) 4F32A9 => 010011110011001010101001

c) C337 => 1100001100110111  

Explanation:

Converting the given hexadecimal numbers to binary:

a) 0x 3AC =>

Binary representation of individual hex digits:

3 = 0011

A=1010

C=1100

so 3AC => 001110101100

b) 0x  4F32A9 =>

Binary representation of individual hex digits:

4 = 0100

F = 1111

3 = 0011

2 = 0010

A = 1010

9 = 1001

so 0x 4F32A9 => 010011110011001010101001

c) 0xC337 =>

Binary representation of individual hex digits:

C = 1100

3 = 0011

7 = 0111

so 0x C337 => 1100001100110111

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