Answer :
Answer:
[tex]log_2(6)=2.584[/tex]
Step-by-step explanation:
Here the logarithm has base 2
[tex]log_2(3^2)=log_2(6)[/tex]
Let
[tex]log_2(6)=x[/tex]
[tex]log_ya=x\\\Rightarrow y^x=a[/tex]
[tex]\\\Rightarrow 2^x=6[/tex]
Now, take logarithm to the base 10
[tex]log 2^x=log6\\\Rightarrow xlog2=log6\\\Rightarrow x=\frac{log6}{log2}\\\Rightarrow x=2.584[/tex]
So, [tex]log_2(6)=2.584[/tex]