Answer :

Answer:

K = 500 x 10⁶ MPa

Explanation:

Given that

P = 10 MPa

V= 0.25 m ³

Reduction in the volume ,ΔV=- 0.005 cm³

We know that 1 m = 1000 cm

ΔV=- 0.005 cm³ = - 0.005  x 10⁻⁶ m³

We know that bulk modulus given as

[tex]K=-\dfrac{P}{\dfrac{\Delta V}{V}}[/tex]

Now by putting the values

[tex]K=-\dfrac{10}{\dfrac{-0.005\times 10^{-6}}{0.25}}[/tex]

We get

K = 500 x 10⁶ MPa

Therefore the bulk modulus of the elasticity will be 500 x 10⁶ MPa.

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