Answer :
Answer:
419.25 lbs
Explanation:
Let iron density [tex]\rho_i[/tex] be 491.5 lb/ft3
and aluminum density [tex]\rho_a[/tex] be 169 lb/ft3
We can calculate the mass of iron that displaces 1.3ft3
[tex]m_i = V*\rho_i = 1.3*491.5 = 638.95 lb[/tex]
Also the mass of aluminum that displaces 1.3 ft3
[tex]m_a = V*\rho_a = 1.3*169 = 219.7 lb[/tex]
So by using aluminum, the airplane can save
638.95 - 219.7 = 419.25 lbs of weight
Answer: a) weight of iron = 638.94lb
b) weight of aluminium = 219.7lb
You have saved 419.24lb when you use aluminium rather than iron.
Explanation:
The weight of an object of equal volume depends mostly on its density.
Density is the mass per unit volume of a material
density p = mass/volume = m/v
Mass m = density × volume = p × v
a) for iron the density of iron is 491.495lb/ft3
For 1.3ft3 of iron we have;
Mass = 491.495 × 1.3
Mass = 638.94lb
b) density of aluminium is 169lb/ft3
For 1.3ft3
Mass = 169 × 1.3
Mass = 219.7lb
c) the amount of weight we safe when we use aluminium is
= Mi - Ma
= 638.94 - 219.7
= 419.24lb