Answered

A parallel plate air capacitor of value C, is charged to a potential V, between
the plates and +9, is charge on one plate. Separation between plates is d. A
dielectric of dielectric constant K = 3 fills the space between the plates. Which
of these quantities will change and why. (i) capacitance (ii) charge (iii) po-
tential difference and (iv) field density?

Answer :

vedanshchauhan16

Answer:

(i) C=3Co

(ii) V=Vo/3

(iii) Decrease

Explanation:

(i) capacitance increase K times.

(ii) As charge remain constant so by using Q=CV

you will get potential decrease by K time.

(iii) Decrease due to induced electric field inside

dielectric material..

E=Eo-Eind

Explanation:

heyaaa hope it helps ☺️✌️

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