Answer :
Neptune's distance from the sun is d₁ = 4.503 x 10⁹ km.
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.
Calculate the number of times d₁ is greater than d₂.
[tex] \frac{d_{1}}{d_{2}} = \frac{4.503 \times 10^{9}}{5.791 \times 10^{7}} = 77.75859[/tex]
Answer: 7.7759 x 10⁻¹ times
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.
Calculate the number of times d₁ is greater than d₂.
[tex] \frac{d_{1}}{d_{2}} = \frac{4.503 \times 10^{9}}{5.791 \times 10^{7}} = 77.75859[/tex]
Answer: 7.7759 x 10⁻¹ times